拉丁方设计是否解决了顺序效应问题？

如题。组内设计最难避开顺序效应问题。拉丁方能解决吗？

可以解决 不过要有前提条件

什么前提？

顺序变量和自变量之间不存在交互作用

引用第3楼psychsen于2010-05-18 14:13发表的  :
顺序变量和自变量之间不存在交互作用

这个前提 我总是想不明白是什么意思

我猜想是可能有这样的一种情况，顺序变量的某一水平在每个自变量水平上的效应都不同，所以在每个自变量的水平上，所有顺序变量的水平的效应和也就不同，顺序效应变量没有被平衡
我猜的，不知道是不是这样

昨天看到一本书上，讲拉丁方设计  能避开顺序效应，但会有carryover effect  （听过两个译法，延续效应 遗留效应）

以下是carryover effect  的解释
A carryover effect is an effect that "carries over" from one experimental
condition to another. Whenever subjects perform in more than one condition (as
they do in within-subject designs) there is a possibility of carryover effects.
For example, consider an experiment on the effect of rate of presentation on
memory. Subjects are presented with a list of words and asked to recall as many
words as they can. In one condition, the words are presented one word per
second; in the other condition, the words are presented two words per second.
The question is whether or not having performed in one condition affects
performance in the second condition. Perhaps learning the first list of words
will interfere with learning the second list because it will be hard to remember
which words were in each list. Or maybe the practice involved learning one list
will make it easier to learn a second list. In either case, there would be a
carryover effect: performance on the second list would be affected by the
experience of being given the first list.

好深奥 占座学习

它就是为了解决组内实验的被试顺序问题的。

啥米是顺序变量？
我觉得有两个前提，一是自变量不要有延续效应。比如切除小鼠的额叶和不切除，这种只能用组间设计。因为切除这个处理时会有延续效应的。
第二是需要平衡的控制变量最好是平稳变化的，均应作用于整个实验过程的。比如，反应时实验的练习效应，因为操作简单，练一两轮就已经达到最高水平，因此只会作用在前一轮或两轮，而不会作用在整个实验过程。这种时候，就不适合用拉丁方或者ABBA，而是要在实验前加练习过程，避免练习效应的作用。

拉丁方只是一种平衡技术。只是说用了这种方法，能更好一点，但实际上是无法完全平衡或消除练习效应或疲劳作用的。